In a recent poll of 2,000 household, 29% had pets.how many households did not have pets?

Lines k and p are perpendicular, neither is vertical and p passes through the origin. Which is greater? A. The product of the sl

AlladinOne [14]

What do we know about those two lines?

They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
1) Both slopes are positive and therefore the product is positive
2) Both slopes are negative and therefore the product is positive (minus by a minus is a plus)

For the y intercepts, we know that the line P passes through the origin.
Therefore its Y intercept is zero.
[draw it if this is not obvious and ask where does it cross the y axis]
Therefore the Y intercept of line K and line P is zero.
[anything multiplied by a zero is a zero]

So we know that the product of slopes is positive, and we know that the product of Y intercepts is zero.
So the product of slopes must be greater.
Answer A

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%283x%5E%7B3%7D%20y%5E%7B2%7D%20z%29%282xy%5E%7B5%7D%20z%5E%7B5%7D" id="TexFormula1" title="(3

castortr0y [4]

<h3 /><h3> $( {3x}^{2} {y}^{2} z) \: ( {2xy}^{5} {z}^{5} ) \\ = 6 {x}^{2} {y}^{2} {xy}^{5} {z}^{6}$ </h3><h3>[ Multiply all digits and variables according to there same value ]</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>

8 0

3 years ago

A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

6 0

3 years ago

What is the difference between 9 thirty sevens and 8 thirty sevens

mojhsa [17]

From what I think of this question, i think of 9x37 and 8x37 OR 9/37 and 8/37. either way 8x37=296 9x37=333 9/37=0.2432 8/37=0.2162

6 0

3 years ago

Read 2 more answers

15% 40% as whole numbers

Alex17521 [72]

Answer: Not possible

Step-by-step explanation: A whole number is an integer or a number without fractions. Both 15% and 40% are less than 1 since they are less than 100%; therefore, it is impossible to express them as whole numbers. They can only be expressed as the mixed numbers of 0.15 and 0.4, or 15/100 and 40/100.

3 0

3 years ago

Read 2 more answers