Answer:
During the first leg, her speed was 61 mph;
During the second leg, her speed was 51 mph
Step-by-step explanation:
In this question, we are told to calculate the speed at which Barbara traveled in both legs of her trip.
Since we do not know the constant speed at which she drove during the first leg of her trip, we can represent this by x. So we can say her speed during the first leg of the trip is x mph.
For the second leg, she drove 10 mph less. Hence her speed here would be (x-10) mph
Let’s start by calculating the distance she traveled during the first leg.
Mathematically, distance traveled is = speed * time = x mph * 4.5h = 4.5x miles
For the second part of the trip, the distance traveled is (x -10) * 6 = (6x - 60) miles
Now the twist to this is that if we add both distances, we get the total distance traveled.
Let’s do that;
4.5x + 6x - 60 = 580.5
10.5x = 580.5 + 60
10.5x = 640.5
x = 640.5/10.5 = 61 mph
In the second leg, her speed would be 61 - 10 = 51 mph
