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slamgirl [31]
2 years ago
7

What percent of 64 is 8

Mathematics
1 answer:
steposvetlana [31]2 years ago
8 0
<span>n/100 * 64 = 8                       </span><span>n/100 = 8/64<span>
n = 8*100/64 = 25/2 = 12.5</span><span>
8 is 12.5% of 64 hope this helps:)</span></span>
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The box plots show the data distributions for the number of text messages Will and Jaime sent each day.What is the difference of
Softa [21]
Hey there!

You can find the medians by referring to the line in the middle of both of the boxes. These indicate the median of the sets of data you have. The first median is at 10 and the other is at 12. 

All you need to do to find the difference is subtract the smaller number from the bigger number. 

12 – 10 = 2

Your difference will be 2, making your second option your answer. Hope this helped you out! :-)
4 0
3 years ago
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Each of the past 8 days, Karen traveled 59.4 miles. How many miles did she travel in all?
madam [21]

Answer:

439.2 miles

Step-by-step explanation:

multiply the days she traveled to the amount of mile she traveled a day

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2 years ago
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6 0
3 years ago
Ron is 8 years old and 40 inches tall. If he grows at the same rate every year, how tall was he when he was 5 years old?
Vadim26 [7]
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5 0
2 years ago
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If lim x-&gt; infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b
MAXImum [283]

We have

\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}

So

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0

The rational term vanishes as <em>x</em> gets arbitrarily large, so we can ignore that term, leaving us with

\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0

and this happens if <em>a</em> = 1 and <em>b</em> = -1.

To confirm, we have

\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0

as required.

3 0
2 years ago
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