Answer:
<em><u>z = -3</u></em>
Step-by-step explanation:
<u>Step 1: Simplify both sides of the equation.
</u>
z+7=−z+1
<u>Step 2: Add z to both sides.
</u>
z+7+z=−z+1+z
2z+7=1
<u>Step 3: Subtract 7 from both sides.
</u>
2z+7−7=1−7
2z=−6
<u>Step 4: Divide both sides by 2.
</u>
<u>2z</u> = <u>−6
</u>
2 2
z=−3
(17-5=12-1=11+8=19-2=(17-3=14)-3=11-3=8-3=5) wait maybe I got this mixed up with somthing else but...
Answer:
a-
b-
c-
Step-by-step explanation:
a.7 y''-7 y =0
Auxillary equation


D=1,-1
Then , the solution of given differential equation

2.
Y=


Substitute in the given differential equation

Hence,
is not a solution of given differential equation
are also not a solution of given differential equation.
y=


Substitute the values in the differential equation

=
Hence,
is a solution of given differential equation.
c.



Substitute the values in the differential equation

Hence,
is a solution of given differential equation.
a-
b-
c-
Answer:
x=11.7
Step-by-step explanation:
When every you have a straight line with a transversal, the line going through the straight line, the two angles will add up to 180.
180=10x+2+5x+3 ---> combine like terms
180=15x+5 ---> subtract 5 to the other side
175=15x ---> divide 15 to the other side
x=11.7
Answer:
Step-by-step explanation:
Whether we divide using long division or using synthetic division, the rule is the same: If, after division, there is no remainder (i. e., the remainder is zero), the divisor binomial is a factor or the associated root is indeed a root/zero/solution.
Divide 5x³+8x²-7x-6 by (x+2) using synthetic division. Use the divisor -2 (which comes from letting x+2 = 0):
--------------------------
-2 / 5 8 -7 -6
-10 4 6
------------------------------
5 -2 -3 0 Since the remainder here is 0, we know that
-2 is a root of 5x³+8x²-7x-6 and that (x+2) is
a factor of 5x³+8x²-7x-6.
Now check out the possibility that (x+1) is a factor of 5x^3 + 8x^2 - 7x - 6:
Use -1 as the divisor in synthetic division:
--------------------------
-1 / 5 8 -7 -6
-5 -3 10
------------------------------
5 3 -10 4
Since there is a non-zero remainder (4), we can conclude that (x + 1) is NOT a factor of the given polynomial expression.