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xxTIMURxx [149]
3 years ago
12

Matt is guiding a group of 94 people he needs to transport them to the start of the hike.He was 2 jeeps that seat 4 each and van

s that seat 8 each.What is the fewest number of vans he will need to transport the group
Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

11 van

Step-by-step explanation:

94 - 2(4)= 86

86 divided by 8 equals 10 but you need to still give the 6 kids a ride so add another van

11 vans

hope this helps

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Another chart question that I don’t know
zloy xaker [14]

From birth to 5yo = 91,200

from 5 to 18yo = 167,000

therefore from birth to 18yo will cost 91,200 + 167,000 which is 258,200

Since the question says per year and thats the total cost of 18 years ( from 0 years to 18), we divide it by 18.

258,200 ÷ 18 = 14,344

Answer a: 14,344

3 0
2 years ago
Please help me! I'll give brainliest!
german
Tan A  = BC/AB = 15/8

answer is B. 15/8
6 0
2 years ago
Read 2 more answers
Which expression is equivalent to
ad-work [718]

Answer:Sorry but none where c there e but no c .

But it would be 16c +2f +13 .

Step-by-step explanation:you need to combine like terms

which are 13c +3c =16c and 9f- 7f=2f and 15-2 =13 .

Hope it helps .

7 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
Who c is the value of the expression [(10^4)(5^2)/10^3)(5^3)]^3 1 2 8 10
Olegator [25]

Answer:

8

10 divided by 5 is 2, and 2 cubed is 8

6 0
3 years ago
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