Tina is bored, very bored. She has decided there is no time like the present to take up a new hobby, paper football creation and
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Answer:
Probability that the proportion of airborne viruses in a sample of 529 viruses would be greater than 8% is 0.9545.
Step-by-step explanation:
For the given population the distribution of air-borne viruses is given as 6%. Now for this the value of Z score is given as
Here
is the sample measure which is 8% or 0.08
- p is the population measure which is 6% or 0.06
- n is the number of samples which is 529
So the Z score is given as
For this the score, the value of probability is calculated from the table as below:
Here value of p(Z<-1.6955) is given as 0.0455
To draw the 2 dimensional representation, we just "open" the box and flatten it. Once we have it opened, we find the area of each side and add them up for the total surface area. See the pic. Let me know if you have questions. :)
