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3 years ago

Solve the system by graphing... 2x-y= -5 x-y=0

Mathematics

1 answer:

kvasek [131]3 years ago

3 0

2x-y= -5

x-y=0 ....> x = y

Substitute x = y into 2x-y= -5

2x - x= -5

x = -5

x = y = -5

Answer

(-5 , -5)

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Y=1/2x+6

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3 years ago

In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed. Use

Mademuasel [1]

Answer:

Claim is true that most medical malpractice lawsuits are dropped or dismissed.

Step-by-step explanation:

Given :In a study of 799 randomly selected medical malpractice lawsuits, it was found that 499 of them were dropped or dismissed.

To Find : Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed.

Solution:

n = 799

x = 499

We will use one sample proportion test

$\widehat{p}=\frac{x}{n}\\\widehat{p}=\frac{499 }{ 799}\\\widehat{p}=0.6245$

We are given that the claim is most medical malpractice lawsuits are dropped or dismissed.

Probability of dropped or dismissed is 1/2

$H_0:p=0.5\\H_a:p>0.5$

Formula of test statistic = $\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

= $\frac{0.6245-0.5}{\sqrt{\frac{0.5(1-0.5)}{799}}}$

= 7.038

p value (z>7.038) is 0

α =0.05

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3 years ago

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

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gtnhenbr [62]

Step-by-step explanation:

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3 years ago

Stormer Company reports the following amounts on its statement of cash flow: Net cash provided by operating activities was $37,0

olchik [2.2K]

Answer:

The ending cash balance is $12,800

Step-by-step explanation:

This is an addition and subtraction problem. We begin with the initial cash balance of $6,800. Next we are "provided" cash from various activities of $37,000. Based on the word used we can tell that this means we have to add this to our initial balance like so,

$6,800 + 37,000 = 43,800$

Now our balance is $43,000. Next we are told that Net Cash "used" in investing activities is $13,600 and "used" in financing activities is $17,400. Based on this word we can tell that this money is being subtracted from our balance.

$$43,000 - 13,600 - 17,400 = 12,800$

Finally, we can see that the ending cash balance is $12,800

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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3 years ago