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3 years ago

Find the difference and the next three terms -10 -20 -30

Mathematics

2 answers:

TiliK225 [7]3 years ago

7 0

The difference is 10, and the next three would be -40 -50 -60

Dafna1 [17]3 years ago

6 0

Answer:

- 40, - 50, - 60

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence.

- 20 - (- 10) = - 20 + 10 = - 10

- 30 - (- 20) = - 30 + 20 = - 10

Thus the difference d = - 10

To obtain a term in the sequence subtract 10 from the previous term

- 30 - 10 = - 40

- 40 - 10 = - 50

- 50 - 10 = - 60

The next 3 terms are - 40, - 50, - 60

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WILL GIVE BRAINLIEST AND 100 PNTS!! Which of the tables represents a function? Table A Input Output 5 3 5 2 4 1 Table B Input Ou

expeople1 [14]

Answer:

Table B

Step-by-step explanation:

Table A Input Output

5 3

5 2

4 1

Has an input that goes to 2 different outputs, not a function

Table B Input Output

1 2

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5 3

one to one relation which is a function

Table C Input Output

0 0

1 2

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Has an input that goes to 2 different outputs, not a function

Table D Input Output

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4 0

3 years ago

Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following

Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3 replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3 replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58) replace n with 58

s_58 = (58/2)*(7/6 + a_58) replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3) replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

s_58 = (58/2)*(299/6)

s_58 = (58*299)/(2*6)

s_58 = 17342/12

s_58 = 8671/6

5 0

2 years ago

A rectangle is 4xcm wide and 2cm long what do you notice

deff fn [24]

The width of the rectangle is twice the length of the rectangle

<h3>How to compare the dimensions of the rectangle?</h3>

The given parameters are:

Width = 4 cm

Length = 2 cm

Express 4 cm as 2 * 2 cm

Width = 2 * 2 cm

Substitute Length = 2 cm in Width = 2 * 2 cm

Width = 2 * Length

This means that the width of the rectangle is twice the length of the rectangle

Hence, the true statement is that the width of the rectangle is twice the length of the rectangle