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3 years ago

To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Mathematics

2 answers:

Marizza181 [45]3 years ago

5 0

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$

chubhunter [2.5K]3 years ago

3 0

Answer: m $\geq -98$

You change the signs and multiply both sides by 7.

Step-by-step explanation:

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2 years ago

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svetoff [14.1K]

Answer:

x=17 plz the brainliest!

Step-by-step explanation:

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2 years ago

Which of the following is a perfect square trinomial?

shutvik [7]

Answer:

Step-by-step explanation:

Take a look at what happens when squaring either of these...

$(ax-by)^2=(ax-by)(ax-by)=a^2x^2-2abxy+b^2y^2\\\\(ax+by)^2=(ax+by)(ax+by)=a^2x^2+2abxy+b^2y^2\\$

Notice a couple of patterns.

1. The last term has a positive coefficient. That rules out answer choices C and D.

2. The coefficient of the middle term is either $+2ab \text{ or } -2ab$ . So what are <em>a</em> and <em>b</em>? <em>a</em> is the square root of the x^2 term and <em>b</em> is the square root of the y^2 term.

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2 years ago