Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?
we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40
the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40
the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40
the answer is
36/40
That is true because if you use the surface area formula, 2(wl+hl+hw), you'll get 250.
Pictures always help; see the one I've attached for reference.
Call the first vector (from HQ to the supply drop) u and the second vector (from supply drop to medics) v. We then want to find w, the vector from the medics to HQ, which corresponds to the vector -(u + v). (This is because u + v is the vector pointing from HQ to the medics; we're talking about the one in the opposite direction.)
Write the vectors in horizontal/vertical component form:
u = (125 km) (cos 235º x + sin 235º y) = (-71.70 x - 102.39 y) km
v = (75 km) (cos 110º x + sin 110º y) = (-25.65 x + 70.48 y) km
Why these angles?
- "55 degrees south of west" is 235º; due west is 180º from the positive horizontal axis, and you add 55º to this
- "20 degrees west of north" is 110º; due north is 90º, so add 20º to this
Add the vectors:
u + v = (-97.35 x - 31.92 y) km
Multiply by -1 to get the vector w:
w = -(u + v) = (97.35 x + 31.92 y) km
The distance covered by this vector is equal to its magnitude:
||w|| = √((97.35 km)^2 + (31.92 km)^2) = 102.45 km
The direction <em>θ</em> is given by
tan<em>θ</em> = (31.92 km)/(97.35 km) ==> <em>θ</em> = 18.15º
Answer:
a=7
Step-by-step explanation:
The image is rendered and attached below.
Triangle WXY is an Isosceles right triangle, since WX=XY.
First, we determine the length of WY using Pythagoras Theorem.

Since triangle WXY is Isosceles, 

Therefore:
Triangle WYZ is a right triangle with WZ as the hypothenuse.
Applying Pythagoras Theorem
