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Vlada [557]
3 years ago
11

Jim is two years older than his sister Mary. The sum of their ages is greater than 32. Describe Mary’s age. Create and inequalit

y for this situation
Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

Let the two ages be j and m, respectively.  Then j+m>32.

Solving for Mary's age, we get   m > 32 - j.  Because j = m + 2, m > 32 - (m+2).

Continue solving for m:  Adding m to both sides of this inequality results in

2m > 32 - 2.  Then 2m > 30, and m > 15.  Mary's age is greater than 15.

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2/15 inches

Step-by-step explanation:

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the axis of symmetry for the graph of the function is f(x) = 1/4x2 bx 10 is x = 6. what is the value of b?
Lady bird [3.3K]

we have

f(x)=\frac{1}{4} x^{2} +bx+10

This is a vertical parabola open upward

The axis of symmetry is equal to the x-coordinate of the vertex

The vertex is the point (h,k)

the equation of the axis of symmetry is x=h

In this problem

x=6

so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

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f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

f(x)+(b^{2}-10)=\frac{1}{4}(x+2b)^{2}

f(x)=\frac{1}{4}(x+2b)^{2}-(b^{2}-10)

remember that

h=6

so

(x+2b)=(x-6)

2b=-6

b=-3

substitute in the equation

f(x)=\frac{1}{4}(x-6)^{2}-((-3)^{2}-10)

f(x)=\frac{1}{4}(x-6)^{2}+1

therefore

<u>the answer is</u>

b=-3


8 0
4 years ago
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3 0
3 years ago
MULTIPLYING POLYNOMIALS
Georgia [21]

(n-4)(n-6) = n^2-10n+24\\\\(a+5)(a-6) = a^2 -a-30\\\\(4b + 6)(b-4) = 4b^2 -10b-24

<em><u>Solution:</u></em>

<em><u>Multiplying polynomials:</u></em>

Multiplying polynomials is same like multiplying numbers

First, multiply the first term in the first parentheses by all the terms in the second parentheses

Now we multiply the second term in the first parentheses by all terms in the second parentheses and add them to the previous terms

1)\ (n-4)(n-6)

(n-4) \times (n-6) = n^2 -6n -4n +24\\\\Simplify\\\\(n-4) \times (n-6) = n^2 -10n + 24

<em><u>Now let us multiply the second given option</u></em>

2)\ (a+5)(a-6)

Multiply them together

(a+5)(a-6) = a^2 -6a + 5a - 30\\\\Simplify\ by\ combining\ the\ like\ terms\\\\(a+5)(a-6) = a^2 -a -30

<em><u>Now let us multiply the third given polynomial</u></em>

3)\ (4b+6)(b-4)

Multiply them together

(4b+6)(b-4) = 4b^2 -16b + 6b - 24\\\\Simplify\ by\ combining\ the\ like\ terms\\\\(4b+6)(b-4) = 4b^2 -10b -24

Thus the given polynomials are multiplied

6 0
4 years ago
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