Answer:
Both fish and bird embryos exhibit gill slits and a tail.
Explanation:
According to embryology, all vertebrates exhibit similar traits and structures at their embryonic stage. It becomes very difficult to differentiate between the embryos of a fish, and that of a bird, or embryo of a fish, and a human. These traits, however, disappear, as the case may be, as the embryo develops into an adult. For example, in the case of the embryo of a fish, and a bird, both shows gills slits at their respective embryonic stage. However, the gill slits in fish develop into gills, whereas in the case of birds, it disappears as the embryo develops into an adult.
Visible light, UV light, and Infrared Radiation I believe.<span />
Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.
Answer:
C
Explanation:
Without crossing over, each chromosome would be either maternal or paternal, greatly reducing the number of possible genetic combinations, which would greatly reduce the amount of genetic variation between related individuals and within a species.
Is C.... I hope this helps
