Answer:
the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Given the data in the question;
Temperature inside ( Sink ) T = 70°F = ( 70 + 460 )R = 530 R
temperature outside ( source )T = 100°F = ( 100 + 460 )R = 560 R
= 800 Btu/min
= 100 Btu/min
Now, from the equation of coefficient of performance of refrigerator;
= Desired output / Required input
= / --------- let this be equation 1
= ( ) /
where is the rate heat gained through the wall
is the heat generation from people and lights and appliances.
Now, lets consider the equation coefficient of performance of refrigerator in terms of temperatures;
= / ( - )
we substitute
= 530 / ( 560 - 530 )
= 530 / 30
= 17.667
so we substitute into equation 1;
= / ---------
= ( ) /
17.667 = ( 100 + 800 ) /
17.667 = 900 /
= 900 / 17.667
= 50.94 Btu/min
= ( 50.94 / 42.53 ) hp
= 1.198 hp ≈ 1.20 hp
Therefore, the minimum power input required for this air-conditioning system is 1.20 hp
Explanation:
Topics
Introduction of research
research process
(a) planning and other preliminary works
(b) literature review
(c) research methodology
research process -2
(a) Data collection
(b)dat analysis, presentation and discussion
(c) report writing
using research findings or conclusion
(a) designing pilot projects( what works)
Answer:
There is no "correct" name, but the scientific name could be meteorite.
Answer:
Both Technician A and technician B are correct.
Explanation: A transistor must have a P-N junction as that is where the positive and negative charges are connected.
A transistor also can be described as a semiconductor which acts as a switch and can be used to amplify currents. Transistors are very key and vital to electronic devices especially the mobile phones in recent times, it helps to ensure that electronic systems perform optimally.
The charges in the P-N junction is controlled by the availability of Positive and negative electrons.
Answer:
a mass of water required is mw= 1273.26 gr = 1.27376 Kg
Explanation:
Assuming that the steam also gives out latent heat, the heat provided should be same for cooling the hot water than cooling the steam and condense it completely:
Q = mw * cw * ΔTw = ms * cs * ΔTw + ms * L
where m = mass , c= specific heat , ΔT=temperature change, L = latent heat of condensation
therefore
mw = ( ms * cs * ΔTw + ms * L )/ (cw * ΔTw )
replacing values
mw = [182g * 2.078 J/g°C*(118°C-100°C) + 118 g * 2260 J/g ] /[4.187 J/g°C * (90.7°C-39.4°C)] = 1273.26 gr = 1.27376 Kg