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liberstina [14]
3 years ago
7

For a given set of input values, a NAND gate produces the opposite output as an OR gate with inverted inputs.A. True

Engineering
1 answer:
Verdich [7]3 years ago
3 0

Answer:

B.

Explanation:

For a given set of input values, A NAND gate produces exactly the same values as an OR gate with inverted inputs.

The truth table  for a NAND gate with 2 inputs is as follows:

0 0    1

0 1     1

1  0    1

1  1    0

The  truth table for an OR gate, is as follows:

0 0    0

0 1     1

1  0    1

1  1     1

If we add two extra columns for inverted inputs, the truth table will be this one:

0 0    1  1       1

0 1     1  0      1

1  0    0  1      1

1  1     0  0     0

which is the same as for the NAND gate, not the opposite, so the statement is false.

This means that the right choice is B.

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Electric heater wires are installed in a solid wall having a thickness of 8 cm and k=2.5 W/m.°C. The right face is exposed to an
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Ymorist [56]
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Suppose we have a database for an investment firm, consisting of the following attributes: B (broker), O (office of a broker), I
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Answer:

Given, FDs are:

S -> D

I -> B

IS -> Q

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a)

"I" and "S" must be there in any candidate key because they do not appear on the right side of any functional dependency.

The only candidate key is: IS

IS -> ISBDQO

b)

Decomposition of R into 3NF: (I, B), (S, D), (B, O), (I, S, Q)

c)

Decomposition of R into BCNF:

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R1 is in BCNF

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Decompose R22 by I → O into R221 = (I, O) and R222 = (I, S, Q).

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R222 is in BCNF.

The decomposition is: (I, B), (S, D), (I, O), (I, S, Q)

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Explanation:

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