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AleksandrR [38]
3 years ago
13

Which is a reason that teen might choose to focus on a friendship and not a romantic relationship

Engineering
2 answers:
andrey2020 [161]3 years ago
4 0

Answer: b. To avoid having distractions

Trust me it’s definitely option b

Mariulka [41]3 years ago
3 0

Answer:

i would say it's option b

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A sheet of steel 3-mm thick has nitrogen atomospheres on both sides at 900 C and is permitted to achieve a steady-state di usion
kati45 [8]

Answer:

X_B = 1.8 \times 10^{-3} m = 1.8 mm

Explanation:

Given data:

Diffusion constant for nitrogen is = 1.85\times 10^{-10} m^2/s

Diffusion flux = 1.0\times 10^{-7} kg/m^2-s

concentration of nitrogen at high presuure = 2 kg/m^3

location on which nitrogen  concentration is 0.5 kg/m^3   ......?

from fick's first law

J = D \frac{C_A C_B}{X_A X_B}

Take C_A as point  on which nitrogen concentration is 2 kg/m^3

x_B = X_A + D\frac{C_A -C_B}{J}

Assume X_A is zero at the surface

X_B = 0 + ( 12\times 10^{-11} ) \frac{2-0.5}{1\times 10^{-7}}

X_B = 1.8 \times 10^{-3} m = 1.8 mm

4 0
2 years ago
Getting the bottom of your feet burned when walking on hot sand is due to what form of energy transmission? group of answer choi
Scilla [17]

Getting the bottom of your feet burned when walking on hot sand is due to a form of energy transmission known as conduction.

<h3>The types of energy transmission.</h3>

In Science, there are three (3) main types of energy transmission and these include the following:

  • Convection
  • Radiation
  • Conduction

In this scenario, we can infer and logically conclude that burning the bottom of your feet when walking on hot sand is primarily due to a form of energy transmission known as conduction because it involves the transfer of thermal energy (heat) due to the movement of particles.

Read more on heat conduction here: brainly.com/question/12072129

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6 0
1 year ago
A one-dimensional plane wall of thickness 2L=80 mm experiences uniform thermal generation of q= 1000 W/m^3 and is convectively c
Eduardwww [97]

Answer:

h=1.99998\ W/m^2.C

k=33.333\ W/m.C

Explanation:

Considering the one dimensional and steady state:

From Heat Conduction equation considering the above assumption:

\frac{\partial^2T}{\partial x^2}+\frac{\dot e_{gen}}{k}=0       Eq (1)

Where:

k is thermal Conductivity

\dot e_{gen} is uniform thermal generation

T(x) = a(L^2-x^2)+b

\frac{\partial\ T(x)}{\partial x}=\frac{\partial\ a(L^2-x^2)+b}{\partial x}=-2ax\\\frac{\partial^2\ T(x)}{\partial x^2}=\frac{\partial^2\ -2ax}{\partial x^2}=-2a

Putt in Eq (1):

-2a+\frac{\dot e_{gen}}{k}=0\\ k=\frac{\dot e_{gen}}{2a}\\ k=\frac{1000}{2*15}\\ k=33.333\ W/m.C

Energy balance is given by:

Q_{convection}=Q_{conduction}

h(T_L-T_{inf})=-k(\frac{dT}{dx}) _L     Eq  (2)

T(x) = a(L^2-x^2)+b

Putting x=L

T(L) = a(L^2-L^2)+b\\T(L)=b\\T(L)=40^oC

\frac{dT}{dx}=\frac{d(a(L^2-x^2)+b}{dx}=-2ax\\Put\ x\ =\ L\\\frac{dT}{dx}=-2aL\\(\frac{dT}{dx})_L=-2*15*0.04=-1.2

From Eq (2)

h=\frac{-k*-1.2}{(40-20)} \\h=\frac{-33.333*-1.2}{(40-20)}\\h=1.99998\ W/m^2.C

7 0
3 years ago
When you are climbing a hill on a bike with different speeds, why does it seem like you are pedaling a lot to cover a short dist
ololo11 [35]

It seems like your pedaling a lot because it takes more energy and is way slower than a regular road. It you switch to the higher gear it will make you go slower because it is made for going down hill or going high speeds and a lower gear will help you more cause its easier and it will make it go faster.

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The corner frequency of this filter in hz is Directly switched the documents to one-of-a-kind Cloud Multi-Regional Storage bucket places in US, EU, and Asia the usage of APIs over HTTP(S).

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1 year ago
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