Answer:
The size of equalization basin is 6105.6 m³
Explanation:
The average flow is:
flow = ∑flow/n = 9.788/24 = 0.408 m³/s
Where n is the number or observations.
The inflow volume is:
where t is the time interval
in the same way it is calculated the inflow volume for each observation
The outflow volume is:
The volume of flow is:
in the same way it is calculated the volume of flow for each observation. According to the file attach, the highest volume is 6105.6 m³
Answer:
peak-hour volume = 1890 veh/h
Explanation:
<u>Determine the peak-hour Volume </u>
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
<u>Back to equation 1 </u>
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
Answer:
14.52 minutes
<u>OR</u>
14 minutes and 31 seconds
Explanation:
Let's first start by mentioning the specific heat of air at constant volume. We consider constant volume and NOT constant pressure because the volume of the room remains constant while pressure may vary.
Specific heat at constant volume at 27°C = 0.718 kJ/kg*K
Initial temperature of room (in kelvin) = 283.15 K
Final temperature (required) of room = 293.15 K
Mass of air in room= volume * density= (4 * 5 * 7) * (1.204 kg/m3) = 168.56kg
Heat required at constant volume: 0.718 * (change in temp) * (mass of air)
Heat required = 0.718 * (293.15 - 283.15) * (168.56) = 1,210.26 kJ
Time taken for temperature rise: heat required / (rate of heat change)
Where rate of heat change = 10000 - 5000 = 5000 kJ/hr
Time taken = 1210.26 / 5000 = 0.24205 hours
Converted to minutes = 0.24205 * 60 = 14.52 minutes
Answer:
The system can be described by a convolution
Explanation:
Thinking process:
If we consider a discrete input to a linear time-invariant system, then the system will be periodic with respect to the period, say N. This therefore, means that the output must also be periodic. The proof is as follows:
The LTI system can be written for the system where:
y (n+N) = ∑
= ∑
From the proof, it turns out that y(y + N) = y(n) for any value of n, then the output will be the periodic with the period N.
Answer:
The maximum possible volume flow of gasoline is 0.543 m^3/s
Explanation:
Power = pressure differential × volume flow rate
Power = 3.8 kW
Pressure differential = 7 kPa
Volume flow rate = power ÷ pressure differential = 3.8 ÷ 7 = 0.543 m^3/s
