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3 years ago

Which statement best describes the graph of x3 − 3x2 − x + 3?

Mathematics

2 answers:

Shkiper50 [21]3 years ago

7 0

Answer:

B. It starts down on the left and goes up on the right and intersects the x-axis at x = −1, 1, and 3.

Step-by-step explanation:

I took the test

e-lub [12.9K]3 years ago

4 0

The second choice. Intersects means cuts the y axis. And if you go to -infinity (figuratively speaking! lol) x^3 dominates and goes to -infinity, way down, the other way for infinity

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Help me with 11 13 10 12 and 14 please

Kazeer [188]

10. d = 20
11. w = 22
12. z = 8
13. idk
14. p = - 8
send me a message or something if this helps ; )

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3 years ago

⦁ It was estimated that 280 people were going to vote. If this was true, how many people would have voted for Goron? Show your w

Alex17521 [72]

Answer:

Goron should get 98 votes

Step-by-step explanation:

The question breaks down to taking 35% of 280.

Votes = 35/100 * 280 = people who will vote for Goron

Votes = 9800 / 100 = people who will vote for Goron.

Votes = 98

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3 years ago

1) 5.4 +(-9.7)<br> Find the sum

harina [27]

Answer:

-4.3

Step-by-step explanation:

5.4 +(-9.7)

= 5.4-9.7

=-4.3

4 0

3 years ago

Read 2 more answers

What is the Range and Mean?

velikii [3]

Answer:

Range：35

Mean：27.6

Step-by-step explanation:

Range is the highest number minus the smallest number 40-5=35

Mean is adding up all the numbers，then divide by how many numbers there are 414 divided by 15

3 0

3 years ago

Read 2 more answers

A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At

Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

The particle starts at rest, so $v(0)=0$ , and we have

$v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t$

Then the position function is

$x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du$

with $x(0)=6$ , so

$x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t$

b. The particle is at rest whenever $v(t)=0$ ; this happens for

$6\sin t=0\implies \sin t=0\implies t=n\pi$

where $n$ is any integer.

3 0

3 years ago