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2 years ago

Is y=1/2+2 linear? and how do you know just by looking at the equation?

Mathematics

1 answer:

saul85 [17]2 years ago

5 0

Answer:

No, it is not

Linear functions are those whose graph is a straight line. A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.

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On the distant plant, Mathology, a sports area covers 7400 yodels2. How many square deckles would this be if 1 deckle = 75.9 yod

STatiana [176]

Answer:

It would be 97.50 square deckles.

Step-by-step explanation:

Given:

On the distant plant, Mathology, a sports area covers 7400 yodels².

1 deckle = 75.9 yodels.

Now, to get the square deckles.

As given, 1 deckle = 75.9 yodels.

So, to get the square deckles by using conversion factor:

75.9 yodels = 1 deckle.

7400 yodels² = $7400\div 75.9$

= $97.50\ deckels ^2.$

Therefore, it would be 97.50 square deckles.

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3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Natali [406]

Answer:

D brainliest?

Step-by-step explanation:

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3 years ago

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18. During a sale, cameras were discounted 30% from their original price of $295.99. How much was each camera during the sale to

attashe74 [19]

Answer:

207.19 is the cost on sale

Step-by-step explanation:

If there is a discount of 30%, we still have to pay 100-30 = 70%

295.99 * 70%

295.99 * .70

207.193

Rounding to the nearest cent

207.19 is the cost on sale

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3 years ago

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Od 2 ( 2 7 1-3 1 3 1-2 6:1-6 b = d = IDONE

Lena [83]

Answer:

$a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}$

Step-by-step explanation:

$\begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

Multiply both the matrices on left side, we find:

$\begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

$\rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

$\rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}$

Comparing the corresponding elements of both the matrices on both sides, we find:

$a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}$

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2 years ago

How do you do 27 divided by 624 in partial quotients

Virty [35]

Answer:

Step-by-step explanation:

For this case we have the following numbers:

624

When dividing both numbers, we observe that:

The partial quotient of the division is equal to 23

The rest of the division is equal to 3.

Note: See attached image to see the procedure of the division between both numbers.

Answer:

the partial quotient of 624 divided by 27 is:

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3 years ago

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