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Margaret [11]
3 years ago
13

Haruka hiked several kilometers in the morning. She only hiked 6 kilometer in the afternoon, which was 25% less she had hiked in

the morning. How many kilometers did haruka hike in all?
Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
7.5 kilometers is what she hiked
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Leto [7]
The formula being used is V=\pi r^2(h/3)

V≈235

V=235.62 to be approximate 
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(THREE CAPITAL LETTERS FOR EACH) ANSWER CORRECTLY !!!!! WILL MARK BRIANLIEST !!!!!! URGENT !!!!!!!!!!
Natasha2012 [34]
FHG is congruent EFH
4 0
2 years ago
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]

It's hard to tell where one set ends and the next starts.  I think it's

A. 25, 36, 44, 51, 62, 77

B. 3, 3, 3, 7, 9, 9, 10, 14

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.

A. 25, 36, 44, 51, 62, 77

That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.

B. 3, 3, 3, 7, 9, 9, 10, 14

Average around 7, sigma around 4, within 2 sigma, seems ok.

C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39

Average around 20, sigma around 8, that 39 is hanging out there past two sigma.  Let's reserve judgement and compare to the next one.


D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82

Average around 74, sigma 8, seems very tight.

I guess we conclude C has the outlier 39.  That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.  



3 0
3 years ago
Read 2 more answers
What is the estimate of 212,514+396,705
Evgesh-ka [11]
Change 212,514 into 215,000.

Change 396,705 into 400,000.

--------

Estimate:

215,000 + 400,000 = 615,000

Therefore:

212,514 + 396,705 ≈ 615,000
4 0
3 years ago
HELP WITH PROBABILITY PWEASEEE <br> (4 questions)
Aliun [14]

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Step-by-step explanation:

We will write the sample space of all options one by one.

a. Rolling a 6 sided die

As the die has six sides numbered from 1 to six then the sample space will be:

S1 =  {1,2,3,4,5,6}

b. Guessing the first initial of a student's name:

As the English language has 26 alphabets, the first initial can be any alphabet so the sample space will be all letters:

S2 =  {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. Tossing two coins

As two coins are tossed, the outcomes will be a combination of two outcomes

S3= {HH,HT,TH,TT}

d. Rolling a 6 sided die and tossing a coin

As the die is rolled and then a coin is tossed. The die's coin will either combine with heads or tails

So,

S4 = {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Hence,

a. {1,2,3,4,5,6}

b. {A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z}

c. {HH,HT,TH,TT}

d. {1T,2T,3T,4T,5T,6T,1H,2H,3H,4H,5H,6H}

Keywords: Sample Space, Probability

Learn more about sample space at:

  • brainly.com/question/11007026
  • brainly.com/question/11207748

#LearnwithBrainly

8 0
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