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3 years ago

X3+y3+z3=k, with k being all the numbers from one to 100

Mathematics

1 answer:

dybincka [34]3 years ago

5 0

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--------------------------------------------------------------------------------------------------------------Question: x3+y3+z3=k, with k being all the numbers from one to 100

--------------------------------------------------------------------------------------------------------------Answer: X = -80538738812075974, Y = 80435758145817515, and Z = 12602123297335631.

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The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Dominik [7]

Answer:

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

Step-by-step explanation:

Given

$(x_1,y_1,z_1) = (1,3,-2)$

$(x_2,y_2,z_2) = (4,5,0)$

$(x_3,y_3,z_3) = (6,3,9)$

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

$C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))$

Substitute values of x and y in the given equation

$C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))$

$C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))$

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

The above is the coordinate of the centroid

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3 years ago

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Answer:

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Step-by-step explanation:

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