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Oksana_A [137]
3 years ago
9

Sarah hiked a path that took her from 34 feet below sea level to 52 feet above sea level . What was the change in her elevation?

​
Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

86 ft

Step-by-step explanation:

<em>First method: Logical thinking</em>

Think of the position 34 ft below sea level as -34.

The position above sea level is 52.

You need to find the distance between -34 and 52.

You go from 34 ft below sea level, -34 to 0. That is 34 ft.

Then you go from sea level, 0 ft, to 52 ft above sea level. That is 52 ft.

The total is 34 ft + 52 ft = 86 ft

Answer: 86 ft

<em>Second method: Calculate a distance in math</em>

The distance between two points on a number line is the absolute value of the difference of their coordinates. The coordinates are -34 and 52. Subtract the numbers in either order, and take the absolute value of the difference.

|-34 - 52| = |-86| = 86

If you did it in the other order, you'd get the same answer.

|52 - (-34)| = |52 + 34| = |86| = 86

Answer: 86 ft

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In a group of eighteen people, each person shakes hands once with each other person in the group. How many handshakes will occur
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The number of handshakes that will occur in a group of eighteen people if each person shakes hands once with each other person in the group is 153 handshakes

In order to determine the number of handshakes that will occur among 18 people, that is, the number of ways we can choose 2 persons from 18 people.

∴ The number of handshakes = ^{18}C_{2}

^{18}C_{2} = \frac{18!}{(18-2)!2!}

^{18}C_{2} = \frac{18!}{16!2!}

^{18}C_{2} = \frac{18\times17\times16!}{16!\times2!}

^{18}C_{2} = \frac{18\times17}{2\times1}

^{18}C_{2} = \frac{306}{2}

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Learn more here: brainly.com/question/1991469

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The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   T(t) =  25 + 72 e^{[-\frac{t}{45} ]}

Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

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              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

            T_{a} = \frac{1}{22} [550  - 1987.12  +  3240]

          T_{a} = 81.95^oC

       

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