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3 years ago

The solution to the inequality. Check all that apply 9x >117

Mathematics

1 answer:

AnnyKZ [126]3 years ago

7 0

First you have to divide the 9 on both sides to get x alone. Next you would have to divide 117 and 9. (117÷9=13) . So x>13

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A water tower that is 120 feet tall casts a 48-foot long shadow. If Shannon is 60 inches tall and standing near the tower, find

Alenkasestr [34]

Answer

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Step-by-step explanation:

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2 years ago

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Solve the systems by the addition method 2x + y = - 1x - 2y = - 4

inna [77]

Answer:

x = -6/5

y =7/5

Step-by-step explanation:

2x + y = - 1

x - 2y = - 4

Multiply the first equation by 2 so we can eliminate y

2(2x + y = - 1)

4x + 2y = -2

Add this to the second equation

4x + 2y = -2

x - 2y = - 4

---------------------

5x + 0y = -6

Divide by 5

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Multiply the second equation by -2 so we can eliminate x

-2(x - 2y = - 4)

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Add this to the first equation

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Divide by 5

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6 0

3 years ago

If n+h/5=f+9/9, then n/5=

Ann [662]

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Question
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$\boxed { \frac{n+h}{5} = \frac{f+9}{9}}$

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Split the fraction on the left
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$\boxed { \frac{n}{5} + \frac{h}{5} = \frac{f + 9}{9}}$

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Take away h/5 from both sides
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$\boxed { \frac{n}{5} = \frac{f+9}{9} - \frac{h}{5}}$

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Change the denominator to be the same
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$\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}$

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Put it into single fraction
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }$

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Rearrange (This step may not be necessary)
------------------------------------------------------------------
$\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }$

$\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}$

6 0

3 years ago

100 IF U GET THIS RIGHT!

Mkey [24]

3/7 because that is the number being added to the zero in the equation

3 0

2 years ago

Read 2 more answers

Please help me find limit

cluponka [151]

9514 1404 393

Answer:

-13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

$\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}$

4 0

3 years ago