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3 years ago

PLZZ NEED HELP ASAPPP :((

Mathematics

2 answers:

crimeas [40]3 years ago

7 0

Answer:

hundredth place is your answer

please mark my answer as brainlist ✌️

and I am Indian I like to make friends

kherson [118]3 years ago

3 0

Answer: I would say it hundredth place

Step-by-step explanation:

You might be interested in

I’m having troubles with this one.

nikklg [1K]

Answer:

239 degrees.

Arc is circumference so length = r * 4.17133691221

Step-by-step explanation:

We eliminate RSQ in degrees = 90 + 31 = 121

So that;

RPQ = 360 -121 = 239 degrees

2pi radius (239/360) = r6.28318530718 (0.66388888888)

= r * 4.17133691221

7 0

4 years ago

Frank makes four bows to decorate a gift basket. Each bow uses7/8 yards of ribbon. The ribbon comes in spool of 3 yards, 5 yards

Alinara [238K]

7/8 yrds of ribbon per bow
if you need 4 bows
7/8 x 4 = 28/8 = 3 1/2 yards of ribbon needed

7 0

3 years ago

Raju is painting the walls and ceiling of a room with length, breadth and height of the room are 10m, 5m, 2m respectively. From

d1i1m1o1n [39]

Answer:

10 cans of paint

Step-by-step explanation:

Find the total area of the room

Divide the answer by 10meter squared.

7 0

4 years ago

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

LET X = Number of parts that are defective

So, it means X ~ Binom(n = 7, p = 0.19)

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= 0.604

Therefore, the probability that fewer than 2 of these parts are defective is 0.604.

8 0

3 years ago

Kendra was asked to find the number of students who planned to attend the evening symphony performance. She was told that 40 per

asambeis [7]

Answer:

Kendra should of divided by 2

Step-by-step explanation:

3 0

4 years ago