$\frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} = \tan \:A \\ \\ LHS = \frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} \\ \\ = \frac{2\sin \:2A.\cos \:2A}{\cos \:2A} \times \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\ \\ = 2\sin \:2A \times \frac{1 - 2 { \cos}^{2}A + 1}{1 - 2 { \cos}^{2}2A + 1 } \\ \\ = 2\sin \:2A \times \frac{2- 2 { \cos}^{2}A }{2 - 2 { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{2(1 - { \cos}^{2}A) }{2 (1- { \cos}^{2}2A) } \\ \\ = 2\sin \:2A \times \frac{1 - { \cos}^{2}A}{1- { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{ { \sin}^{2}A}{{ \sin}^{2}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ \sin}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \: A } \\ \\ = \frac{ { \sin}A}{ \cos \: A } \\ \\ = tan \: A \\ \\ = RHS \\$

7 0

3 years ago

Hey friends!! Can you please help me on my homework? My teacher said if you are missing any work from past few days to do it and

scoray [572]

1- B
2- C
3- B
4- D
5- D
6- C
7- B
8- C
9- C
10- C

Hope I helped you!!
I really think that I got them all right.. PLEASE tell me if I got any wrong so that I can change them :) Its been a while since I've done this... XD

3 0

2 years ago

Cell phone company offers the followings plan: Monthly charge (which includes 400 minutes) for $30 and

xxMikexx [17]

Answer:

who are you not going to be at work at the

4 0

2 years ago