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MrRissso [65]
2 years ago
14

Trapezoid W′X′Y′Z′ ​ is the image of trapezoid WXYZ under a dilation through point C.

Mathematics
2 answers:
IRINA_888 [86]2 years ago
4 0
Formula for scale factor
=image devide object
the answer is c

Snezhnost [94]2 years ago
4 0

Answer:

Option C.

Step-by-step explanation:

Two trapezoids W'X'Y'Z' and WXYZ have been given in the figure attached.

Trapezoid WXYZ has been dilated to form another trapezoid W'X'Y'Z'.

We have to find the scale factor by which WXYZ was dilated.

Dilation factor = \frac{\text{Trapezoid W'X'Y'Z'}}{\text{Trapezoid WXYZ}} = \frac{W'X'}{WX}

= \frac{6}{8}

= \frac{3}{4}

Therefore, \frac{3}{4} is the dilation factor by which trapezoid WXYZ was dilated.

Option C is the answer.

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6 0
3 years ago
Homer and Bart plan to buy one computer for $499.00 strictly for gaming
kati45 [8]

Answer:

Part A: T(x) = $49.99x + $499.00

Part B: $748.95

Part C: T(x) = $49.99x + $24.99y + $499.00

Part D: $773.93

Step-by-step explanation:

Part A:

Let x represent the amount of games bought. Let T(x) represent total cost.

T(x) = $49.99x + $499.00

Part B:

T(x) = $49.99(5) + $499.00

T(x) = $249.95 + $499.00

T(x) = $748.95

Part C:

Let y represent the amount of controllers bought.

T(x) = $49.99x + $24.99y + $499.00

Part D:

T(x) = $49.99(4) + $24.99(3) + $499.00

T(x) = $199.96‬ + $74.97 + $499.00

T(x) = $773.93

7 0
3 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
-BARSIC- [3]

Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))

The slant asymptote is y=3/2x+3/4

6 0
3 years ago
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