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MrRissso [65]
3 years ago
14

Trapezoid W′X′Y′Z′ ​ is the image of trapezoid WXYZ under a dilation through point C.

Mathematics
2 answers:
IRINA_888 [86]3 years ago
4 0
Formula for scale factor
=image devide object
the answer is c

Snezhnost [94]3 years ago
4 0

Answer:

Option C.

Step-by-step explanation:

Two trapezoids W'X'Y'Z' and WXYZ have been given in the figure attached.

Trapezoid WXYZ has been dilated to form another trapezoid W'X'Y'Z'.

We have to find the scale factor by which WXYZ was dilated.

Dilation factor = \frac{\text{Trapezoid W'X'Y'Z'}}{\text{Trapezoid WXYZ}} = \frac{W'X'}{WX}

= \frac{6}{8}

= \frac{3}{4}

Therefore, \frac{3}{4} is the dilation factor by which trapezoid WXYZ was dilated.

Option C is the answer.

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Answer:

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Step-by-step explanation:

It is given that for first 30 km, the speed of bicyclist is v km/hour

time taken to cover first 30 km is given by

t_{1} =\frac{30}{v}           ( time=\frac{distance}{speed})

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so the speed to cover next 17 km = v+2

time taken to cover next 17 km is given by

t_{2} =\frac{17}{v+2}

now total time t spent by the bicyclist to cover entire trip is given by

t=t_{1} +t_{2}

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now if v=18 , we have

t=\frac{30}{18} +\frac{17}{20}

now to add fractions we make the denominator same

Hence we will find the LCM of 18 and 20

LCM of 18 and 20 = 180

now we need to make both the denominator equal to 180

t=\frac{30(10)}{18(10)} +\frac{17(9)}{20(9)}t=\frac{300}{180} +\frac{153}{180} =\frac{300+153}{180}

t=\frac{453}{180} =2.52 hours (approx)

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