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Sergeu [11.5K]
2 years ago
12

PLS HELP PLSS IM DYinG IN A FIRE PLS SAIN NICK WONT LET ME OUT OF THIS FIRE IF I DONT ANSEWR HE QUESTION PLSSSSSSSS

Mathematics
2 answers:
OlgaM077 [116]2 years ago
6 0

Answer:

The answers are 2πr, πr², and πd

Step-by-step explanation:

Circumference is area×π×2, and diameter is area×2, so it can also be d×π.

zloy xaker [14]2 years ago
5 0

it the second and last answers pi(d) and 2pi(r)

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Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, q_1 = Q- r \times Q

q_1 = Q(1-r)\cdots(i)

The value of quantity after 2 months, q_2 = q_1- r \times q_1

q_2 = q_1(1-r)

From equation (i)

q_2=Q(1-r)(1-r)  \\\\q_2=Q(1-r)^2\cdots(ii)

The value of quantity after 3 months, q_3 = q_2- r \times q_2

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Similarly, the value of quantity after n months,

q_n= Q(1- r)^n

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

q_{48}=Q(1-r)^{48}

Putting Q=6200 and r=5.5%=0.055, we have

q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32

Hence, the value of quantity after 4 years is 410.32.

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