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3 years ago

Can someone please answer. There is a picture. There is only one problem. Thank you so much!!!

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

This is false, because again, a hyperbola could have /many/ different orientations and still technically be a hyperbola. It doesn't /in general/ have to be symmetric about the lines y = k or x = h, but it might be symmetric about, say, the line x + y = k + h, if it were rotated 45° relative to the "usual" equation. sorry for the long answer lol

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A study among first-year students at a state university showed that in general students who skipped more classes earned lower gr

Alex Ar [27]

Answer:

The numerical value of the correlation between number of classes skipped and grade index is 0.60.

Step-by-step explanation:

In statistics R² is a measure that is used to determine the proportion of variation in the dependent variable that can be explained by the independent variable. The value of R² is compute by squaring the correlation coefficient (r) between the dependent and independent variable.

$R^{2}=(r)^{2}$

In this case the dependent variable is the grades and the independent variable is the number of classes skipped.

The R² between the grades and the number of classes skipped is 36% or 0.36.

Compute the value of r as follows:

$R^{2}=(r)^{2}\\r=\sqrt{R^{2}}\\ =\sqrt{0.36} \\=\pm0.60$

Thus, the correlation between number of classes skipped and grade index is ±0.60.

4 0

3 years ago

Please help me with this math problem!! :)

jok3333 [9.3K]

Answer: so what grade math is this

Step-by-step explanation:

4 0

2 years ago

chris has 5 1/2 cups of water in a pitcher. He pours 3/8 cup of water into a glass. How many cups of water is left in the pitche

swat32

There's 5 1/8 cups of water left in the pitcher.

- 5 1/2 = 11/2

- 11/2 = 44/8

- 44/8 - 3/8 =41/8

- 41/8 = 5 1/8

7 0

3 years ago

What is the sum of the last four terms of the series 7+9+11+...+21

Doss [256]

7 - 9 = 2 9 - 11 = 2 You should see that the series just increases by +2 therefore you can figure out what the last four terms are and then add them up one of the last terms given is 21

7 0

3 years ago

What is an extraneous solution to the equation b/b-3 -5/b=3/b-3 ?

storchak [24]

$\frac{b}{b-3} - \frac{5}{b} = \frac{3}{b-3} \\ \frac{ b^{2} -5(b-3)}{b(b-3)} =\frac{b}{b-3} \\ \frac{ b^{2} -5b+15}{b^2-3b} =\frac{b}{b-3} \\ (b-3)(b^{2} -5b+15)=b(b^2-3b) \\ b^3-8b^2+30b-45=b^3-3b^2 \\ 5b^2-30b+45=0 \\ b^2-6b+9=0 \\ (b -3)(b-3)=0 \\ b=3$

To check: 3/3-3 - 5/3 = 3/0 - 5/3 which is not defined.

Therefore, b = 3 is an extraneous solution.

5 0

3 years ago

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