Answer:
lower 95% Cl is 0.292
Step-by-step explanation:
p^ = 0.4783
n = 23
for 95% Cl,
z = 1.9600
Inputting all the available data into P as attached below
LCL = 0.292
UCL = 0.670
therefore, lower 95% Cl = 0.292
Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
Answer:
0, undefined
Step-by-step explanation:
Slope=∆y/∆x
= 8-1 / 1-1
=7/0
= undefined
It’s negative slope since it’s going to the left
Answer:
Discount = Original Price x Discount %/100
Discount = 2.88 × 1/100
Discount = 2.88 x 0.01
You save = $0.03
Final Price = Original Price - Discount
Final Price = 2.88 - 0.0288
Final Price = $2.85
