Answer:
6 chairs
8 desks
Step-by-step explanation:
First, we assume that all 14 items he bought were chairs, if that was to be true then the office manager would spend...
125 x 14 = 1750$
We see that he spent less then he should have so now we start to substitute desks instead of chairs, and we have to keep in mind that if we change 1 chair to a desk then the total will increase by...
515 - 125 = 390$
Now we just find the difference between the needed total and the total that we get if the office manager would by only chairs and then divide the result by 390 in order to find the number of desks, and so we get...
(4870 - 1750) / 390 = 3120 / 390 = 8 desks
And now that we know the number of desks we just subtract the number of desks from 14 and get the number of chairs, and so...
14 - 8 = 6 chairs
4,003,052 is the answer to the problem
Answer:
(a) 2996 units
(b) 1897 units
Step-by-step explanation:
p = 10,000(1 - 3/3 + e^-0.001x)
(a) p = $500
500 = 10,000(1 - 1 + e^-0.001x)
500/10,000 = e^-0.001x
e^-0.001x = 0.05
-0.001x = In 0.05 = -2.996
x = -2.996/-0.001 = 2996 units
(b) p = $1500
1500 = 10,000(1 - 3/3 + e^-0.001x)
1500/10,000 = (1 - 1 + e^-0.001x)
0.15 = e^-0.001x
-0.001x = In 0.15 = -1.897
x = -1.897/-0.001 = 1897 units
Answer:
The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.
Step-by-step explanation:
We can model this question with a binomial distribution random variable.
The sample size is n=60.
The probability that the relay come from supplier A is p=2/3 for any relay.
If we use a normal aproximation, we have the mean and standard deviation:
The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:
