3 years ago

I need help!!! Because this is due

Engineering

2 answers:

xenn [34]3 years ago

7 0

I don’t understand either

vladimir1956 [14]3 years ago

3 0

Answer:

see attached

Explanation:

if you are looking for the correct measurement... see attached image

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3 years ago

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Consider a refrigerator that consumes 320 W of electric power when it is running. If the refrigerator runs only one quarterof th

ryzh [129]

Answer:

$5.184

Explanation:

The cost can be calculated using the formula: $Cost = Load \ factor \times Number \ of \ hours \ \\M_{month} = M_{units} \times W\\$

Before using this, we require the following conversions:

320 W → kW:

$\frac {320}{1000} = 0.32$

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$30 \times 24 = 720$

Using the above stated formula:

$M_{month} = 0.09 \times 0.32 \times \frac{1}{4} \times 720 = 5.184$

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3 years ago