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elena-s [515]
3 years ago
6

The ultimate BOD of a river just below a sewage outfall is 50.0 mg/L, and the oxygen deficit at the outfall D0 is 2.0 mg/L. The

saturation value of dissolved oxygen is 11.0 mg/L. The deoxygenation rate coefficient kd is 0.30/day, and the reaeration rate coefficient kr is 0.90/day. The river is flowing at the speed of 45.0 miles per day. The only source of BOD on this river is this single outfall.
A. Find the critical distance downstream at which DO is a minimum.
B. Find the minimum O.

Engineering
1 answer:
hram777 [196]3 years ago
6 0

Answer:

A. Find the critical distance downstream at which DO is a minimum. = 76.14 miles

B. Find the minimum O. = 0.983mg/l

Explanation:

check the file for more explanations

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ANSWER:

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Therefore;

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We know that at room temperature, which is 25°C the viscosity of water is 8.9×10^-4pa.s . We can find the viscosity of water at 4°C by cross multiplying.

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U25°C = 0.00356°C.pa.s

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Imputing the values into poiseuille equation above.

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Therefore;

Q = 0.16547887ft3/s

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