Answer:
The correct answer is option (c) An experimental observation that the velocity of a fluid in contact with a solid surface is equal to the velocity of the surface.
Explanation
Solution:
When a fluid is in proximity to the boundary the solid and the velocities are the same or uniform for the fluid and the surface, no slip condition does not exist.
However, because the no-slip meets the expectations for gas and liquids, this condition no way connected in this case of two solid in proximity.
hence, the other options are wrong here.
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness = 92 Mpa√m
yield strength σ = 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length = 1/π( / Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection
Bend surface in water! Hopefully this helps, I looked it up!
Answer:
The answer is 2217.32m³
Explanation:
Given that:
V₂ = (15 + 5/2) * 3 * 100 = 3000 m³
r₁ = 21.7kN/m3
w (water) = 11.4%.
e₂ (void ratio) = 0.47
V₁ = ?
Now,
rd₁ = r₁/1 + w₁ = 21.7/1 +(11.4/100)
= 19.47 kN/m3
Thus,
rd₂ = r₁/1 + e₂ = 21.7/1+ 0.47 = 14.76 kN/m3
Then,
V₁/V₂ = rd₁/ rd₂
V₁ = 3000 * 14.76/19.97
V₁ = 2217.32m³
Therefore, volume that should be excavated from the borrow pit is 2217.32m³