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marshall27 [118]
3 years ago
8

The table below compares the cost of living in New York and Los Angles, with the number representing percentages of national ave

rage.
If the national average for a gallon of gas is $2.74, how much should you expect to pay for gas in New York versus Los Angles.

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

The correct option for the answer is C.) $3.29 / $2.96

Step-by-step explanation:

i) national average for a gallon of gas = $2.74

ii) for transportation New York is 1.2 times the National average

therefore one gallon of gas in New York will cost = 1.2 \times $2.74 = $3.29

iii)for transportation Los Angeles is 1.08 times the National average

therefore one gallon of gas in New York will cost = 1.08 \times $2.74 = $2.96

Therefore you should expect to pay for gas in New York versus Los Angeles C.) $3.29 / $2.96

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For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

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3 years ago
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Answer:

a)400V2 plus 3,600 m2

Step-by-step explanation:

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S = a * b  where a - <span>length and b - width
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