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3 years ago

Would love some help on this! Please include step by step Have a good day!

Mathematics

1 answer:

Effectus [21]3 years ago

5 0

$- 24 - 16x( - 1) \\ 6 { }^{2} \div 9$

negative 24 minus 16x (-1) divided by 6^2 divided by 9

ANSWER

four divided by 81 and than X minus 24

$4 \div 81x - 24$

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The value of y varies directly with x. Which function represents the relationship between x and y if y = 20/3 ?

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3 years ago

A garden table and a bench cost $450 combined. The cost of the garden table is two times the cost of the bench. What is the cost

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3 years ago

8x−5x+4−x=Ax+8. Anyone know

lora16 [44]

Answer:

a = $\frac{2x-4}{x}$

x = $\frac{4}{-a+2}$

Step-by-step explanation:

Let's solve for a.

8x−5x+4−x=ax+8

Step 1: Flip the equation.

ax+8=2x+4

Step 2: Add -8 to both sides.

ax+8+−8=2x+4+−8

ax=2x−4

Step 3: Divide both sides by x.

Let's solve for x.

8x−5x+4−x=ax+8

Step 1: Add -ax to both sides.

2x+4+−ax=ax+8+−ax

−ax+2x+4=8

Step 2: Add -4 to both sides.

−ax+2x+4+−4=8+−4

−ax+2x=4

Step 3: Factor out variable x.

x(−a+2)=4

Step 4: Divide both sides by -a+2.

Hope this helps!

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2 years ago

Help now! Find the area of this. 210 420 105 1092

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Heyyyyyy, use https://www.bartleby.com/ it has helped me out a lot . Its actual tutors/teachers who answer your questions in about 30 minutes !!!!!!!!

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3 years ago

Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x

svetlana [45]

Hello,

$sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\

$
==============================================================
$2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 
$

8 0

3 years ago

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