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3 years ago

Why H +ve acts as lewus acid? Why NH3 acts as bronsted-lowery base? Why BF3 acts as Lewis acid? Make it easy and simple.. ✨

Chemistry

1 answer:

Delvig [45]3 years ago

5 0

Explanation:

Unlike the traditional definition of defining acid as any substance that can react with a base to form salt and water, there are two other definition of acid.

These are lewis acid and bronsted lowry acid.

Lewis acid is any substance that can accept a pair of non bonding electrons. This is why H+ is able to as a lewis acid.

Bronsted lowry definition on the other hand is as follows; A brosted lowry acid is any species that can donate a proton to another molecule. A bronsted lowry base is any specie that can accept a proton from another molecule. NH3 is able to accept a proton, hence it is termed as a bronsted lowry base.

BF3 act as a lewis acid because it can accept accept a pair of non bonding electrons. Generally; an atom, ion, or molecule with an incomplete octet of electrons can act as an Lewis acid.

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Chemists need the mole concept to bridge the gap between the microscopic world of atoms to the macroscopic world of humans. As you know, the molecular level consists of particles that are invisible to us.

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3 years ago

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Which types of asexual reproduction could be seen

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Answer:

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4 years ago

Calculate how many moles of Ca(OH)2 are needed to produce 4.8 x 1024 NH3 molecules, according to the following equation

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3 years ago

As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is

chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

I hope it helps!

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3 years ago

For the reaction: 3 H2(g) + N2(g) <--> 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [

masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.