Question

If the accepted value for the mass of an object is 20.0g and the student found that the mass of the object was 20.5g what is the student’s percent error?

Answer 1

Answer:

Results

The percent error between 20 and 20.5 is 2.5%

Explanation:

Percent Error = | (20.5 − 20) / 20 | × 100 = | (0.5) / 20 | × 100 = | 0.025 | × 100 = 2.5% (three decimal places)Percent Error = 2.5%