Answer:
The following three isomeric structure are given below.
Explanation:
Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂
Ester #1: methyl 1-methylcyclobutanecarboxylate
Ester #2: (E)-methyl 3-methyl-3-pentenoate
Ester #3: isopropyl 2-methylpropenoate
Answer:
D. Solution A has more concentrated acid than solution B and acid in solution A is also a weaker acid than that in solution B.
Explanation:
As it has been said in the question that the volume to reach the equivalence point of the solution A is twice the volume of solution B, this is because the acid in the solution A is more concentrated than B that's why more NaOH was required to reach to the equivalence point.
Since the pH at the equivalence point was greater for solution A that means the acid in solution A was a weak acid that's why the pH raised more as the NaOH was added to the solution.
Molecules are continuously colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces.The more particles that hit the walls, the higher the pressure.
<u>Answer:</u> The percentage abundance of
and
isotopes are 75.77% and 24.23% respectively
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 62.9396 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 64.9278 amu
Fractional abundance of
isotope = 1 - x
- Average atomic mass of copper = 63.546 amu
Putting values in equation 1, we get:
![63.546=[(62.9396\times x)+(64.9278\times (1-x))]\\\\x=0.6950](https://tex.z-dn.net/?f=63.546%3D%5B%2862.9396%5Ctimes%20x%29%2B%2864.9278%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.6950)
Percentage abundance of
isotope = 
Percentage abundance of
isotope = 
Hence, the percentage abundance of
and
isotopes are 69.50% and 30.50% respectively.
Answer:
C. NaCl and A. Water(H2O)
Explanation:
Products are on the right side of the equation, reactants are on the left.