Answer:
Step-by-step explanation:
Let the speed of the car is c and speed of the plane is p.
<h3>We are given:</h3>
The speed of the plane is 7 times the speed of the car
The distance traveled is
The time difference to travel this same distance is 3 hours.
<h3>We know that:</h3>
- d = ts, where d- distance, t- time, s - speed
Find the time for car and plane and their difference.
<h3>Car</h3>
<h3 /><h3>Plane</h3>
- t = d/s = 315/p = 315/(7c) = 35/c
<h3 /><h3>The difference</h3>
<u>Solve it for c:</u>
- (315 - 45)/c = 3
- 270/c = 3
- c = 270/3
- c = 90 km/h
Now find the speed of plane:
As we see, Jenny is right
Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5 where T(1)=11
T(9)=6(9)+5=59
I think you mean 48. 4 * x = 48. x = 48/4 = 12
We immediately note that 3 and 9 are multiples. Therefore, they are factorable. 9 goes into 3 three times, and 3 goes into three 1 time. Therefore, we can take out three from the whole expression to get 3(c - 3).
