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cricket20 [7]
2 years ago
14

Zhane picked 28 cherries. 1/7 of them are bad. How many groups of cherries would she have to divide them into to find out how ma

ny were bad? *
Mathematics
1 answer:
castortr0y [4]2 years ago
4 0
She would have 7 groups of cherries
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The speed of light is 299,792.458 .
andrezito [222]

Answer:

a

when you round the number up it becomes 300,000.00

3 0
2 years ago
What is the sum of the numbers in the series? 15 + 11 + 7 + . . . + (–129)
babymother [125]
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109


Using AP, T(n)=15+11+7+....-129
T(n)=19-4n  => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
3 0
3 years ago
Marcus wants to determine how age and weight are related to exercise preference in his town. He selects a simple random sample o
mario62 [17]

Answer:

He will be unable to tell whether a difference in exercise preference is related to a difference in age or to a difference in weight

Step-by-step explanation:

age could be a factor to exercise as well as weight so both affect the outcome so he has two samples

3 0
3 years ago
Od<br> 2<br> (<br> 2 7 1-3<br> 1 3 1-2<br> 6:1-6<br> b =<br> d =<br> IDONE
Lena [83]

Answer:

a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}

Step-by-step explanation:

  • \begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Multiply both the matrices on left side, we find:

  • \begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Comparing the corresponding elements of both the matrices on both sides, we find:

  • a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}
7 0
2 years ago
Evaluate the following expression.
melisa1 [442]

Answer:

40

Step-by-step explanation:

y = 4

z = 2

8y + 12 - 2z

8(4) + 12 - 2(2)

32 + 12 - 4

44 - 4

40

8 0
2 years ago
Read 2 more answers
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