Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.
Carl had .5 left of a snack bar.
Dave had .3 left of a snack bar.
Tony had .5 left of a snack bar.
Gary had .0 left of a snack bar.
Tryone had .7 left of a snack bar.
If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.
Answer:
0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Poisson distribution with an average of three errors per page
This means that 
What is the probability that a randomly selected page does not need to be retyped?
Probability of at most 3 errors, so:

In which
Then

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.
0.875 as a fraction is 7/8 because 875/100 is equal to 7/8
Answer:
A. h(x)=4x+2
Step-by-step explanation:
Because it's shifted to the left, you would subtract three units from 5, resulting in 4x+2. Hope this helps, have a nice day! :)