Answer: 7 times 4
Step-by-step explanation:
Answer:
positive is the correct answer
Let P(a, b) be a point on the coordinate plane. Then the following hold:
i) If a>0, b>0 then P is in the I.Quadrant.
ii) If a<0, b>0 then P is in the II.Quadrant.
iii) If a<0, b<0 then P is in the III.Quadrant.
iv) If a>0, b<0 then P is in the IV.Quadrant.
v) If a=0 and b is positive or negative, then P is on the y-axis.
vi) If b=0 and a is positive or negative, then P is on the x-axis.
Since we have: a=0, and 19 positive, then this point is on the y-axis.
Answer: y-axis
The answer to this is (x+6)(x+2)
Originally we have
length = x
width = x-2
since the width is 2 inches smaller than the length
now let's triple each dimension. Multiply the expressions by 3 to get
new length = 3*x
new width = 3*(x-2) = 3x-6
Now onto the area
area = (length)*(width)
area = (3x)*(3x-6)
area = 3x*3x-3x*6
area = 9x^2 - 18x
So the new larger rectangle has area of 9x^2-18x
