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3 years ago

Find the number of four-digit numbers which are not divisible by 4?

Mathematics

1 answer:

SOVA2 [1]3 years ago

3 0

Answer:

6750

Step-by-step explanation:

4 digit numbers are 1000,1001,1002,...,9999

let numbers=n

d=1001-1000=1

9999=1000+(n-1)1

9999-1000=n-1

8999+1=n

n=9000

now let us find the 4 digit numbers divisible by 4

4| 1000

______

| 250

4 |9999

_____

| 2499-3

9999-3=9996

so numbers are 1000,1004,1008,...,9996

a=1000

d=1004-1000=4

let N be number of terms

9996=1000+(N-1)4

9996-1000=(N-1)4

8996=(N-1)4

N-1=8996/4=2249

N=2249+1=2250

so number of 4 digit numbers not divisible by 4=9000-2250=6750

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In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a

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Answer:

The answer is " $\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}$ "

Step-by-step explanation:

Given value:

Temp-maximum= $18^{\circ}$

Temp. minimum = $3^{\circ}$

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The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:

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$B = \frac{2 \pi}{24}\\\\$

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Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

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Answer:

Step-by-step explanation:

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Hello,

Very nice as problem.

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and
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since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

2 years ago