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marusya05 [52]
3 years ago
14

Please help both questions 

Physics
1 answer:
Evgen [1.6K]3 years ago
7 0
Number 3 is C and number 4 i really don't know because i can't see the answer choices 
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Cancer causing agents are also called
BARSIC [14]
Cancer-causing agents are also called <span>carcinogens</span>
5 0
4 years ago
What kind of line on a distance vs. time graph indicates that the object is accelerating?
suter [353]

Answer: a curved line

Explanation: a straight line indicates that the object is moving at a constant velocity because it has one slope, but a curved line on a distance-time graph indicates that the velocity is constantly changing because the slope is changing, which is acceleration. the line could be curved in any direction, as long as it shows a change in slope.

7 0
3 years ago
The VLBA (Very Long Baseline Array) uses a number of individual radio telescopes to make one unit having an equivalent diameter
Alex787 [66]

Answer:

d₂=232.8 m

Explanation:

We know that formula for resolution given as

θres = 1.22 λ/d

Where

λ=wavelength

d=diameter

Given that resolution should be same.So we can say that

1.22 λ₁/d₁= 1.22 λ₂/d₂

λ₁/d₁= λ₂/d₂

d_2=\dfrac{\lambda _2}{\lambda _1}d_1

Given that

λ₂=582 nm

λ₁=2 cm

d₁=8000 km

d_2=\dfrac{582\times 10^{-9}\times 8000\times10^3}{0.02}\ m

d₂=232.8 m

8 0
3 years ago
Hedea made a study chart about nuclear energy. Which best describes the error in Hedea’s chart? The nuclei of atoms are split ap
Lerok [7]

Option (d) is correct.Fission and fusion convert nuclear energy to both radiant and thermal energy.

fission is a process in which bigger nucleus breaks into two or more smaller nuclei with the liberation of a large amount of energy.

Fusion is a process in which two small nuclei fuse together to from an intermediate size nucleus with the liberation of tremendous amount of energy

During fission and fusion, energy is released in the form of both light (radiation) and heat.we can then convert that energy into useful form.

5 0
3 years ago
Read 2 more answers
An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of
joja [24]

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

Given that

The wavelength of the wave, λ = 435 nm

Amplitude of the electric field, E(max) = 2.7*10^-3 V/m

a)

The frequency of the wave can be found by using the formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b)

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c)

1T = 1 (V.s/m^2)

8 0
4 years ago
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