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marusya05 [52]
3 years ago
14

Please help both questions 

Physics
1 answer:
Evgen [1.6K]3 years ago
7 0
Number 3 is C and number 4 i really don't know because i can't see the answer choices 
You might be interested in
When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.
Akimi4 [234]
  • Mass=1167kg
  • Initial velocity=u=10m/s
  • Acceleration=a=4m/s^2
  • Work done=105J=W
  • Final velocity=v=?
  • Force=F
  • Distance=d

Apply Newton's second law

\\ \tt\hookrightarrow F=ma

\\ \tt\hookrightarrow F=1167(4)=4668N

Now

\\ \tt\hookrightarrow W=Fd

\\ \tt\hookrightarrow d=\dfrac{W}{F}

\\ \tt\hookrightarrow d=\dfrac{105}{4668}

\\ \tt\hookrightarrow d=0.022m

Now

  • d be s

According to third equation of kinematics

\\ \tt\hookrightarrow v^2=u^2+2as

\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)

\\ \tt\hookrightarrow v^2=100+8(0.022)

\\ \tt\hookrightarrow v^2=100+0.176

\\ \tt\hookrightarrow v^2=100.176

\\ \tt\hookrightarrow v=10.001m/s

8 0
2 years ago
Does there appear to be a simple mathematical relationship between the acceleration of an object (with fixed mass and negligible
KengaRu [80]

Answer:

the net force applied to an object is directly proportional to the acceleration undergone by that object

Explanation:

This verbal statement can be expressed in equation form as follows:

a = Fnet / m

7 0
3 years ago
(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —
Sergeu [11.5K]

Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

             A = 0.07129 m²

b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

8 0
3 years ago
The answer please to this and how it’s urgent
oksano4ka [1.4K]

Answer:

rA = 9 i + 9 j

rB = 12 i - 9 j

rB - rA = 3 i - 18 j

so distance in between them

= √[3×3 + 18 × 18 )

= √(9+324)

= √333

= 18.3 m

6 0
4 years ago
How much larger is the acceleration with two people pushing on one side of the cart compared to only one person pushing the cart
il63 [147K]
As we said to the two people name A and the single person nameB.as every person make an acceleration 60ms2.so group A has more acceleration then group B. because in A there are two person so we add 60+60=120ms2. so group A can produce 120ms2 while groupB can produce 60ms2. i hope it will help you.

6 0
3 years ago
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