Answer:
Part(a): The frequency is
.
Part(b): The speed of the wave is
.
Explanation:
Given:
The distance between the crests of the wave,
.
The time required for the wave to laps against the pier, 
The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is
.
Also, the time required for the wave for each laps is the time period of oscillation and it is given by
.
Part(a):
The relation between the frequency and time period is given by

Substituting the value of
in equation (1), we have

Part(b):
The relation between the velocity of a wave to its frequency is given by

Substituting the value of
and
in equation (2), we have

The correct answer is A. 250N
Work is a product of force and distance.
That is, work done=force×distance
Therefore substituting for the values in the question:
500J=force×2m
force= 500Nm/2m=250N
another unit for work done is Nm as force as the SI unit of force is newtons and distance in meters
Answer:
300J
Explanation:
Work done = Force x the distance travelled in the direction of the force
=300 x 1
=300J
Answer:
12.14 cm
Explanation:
mass, m = 15.5 kg
frequency, f = 9.73 Hz
maximum amplitude, A = 14.6 cm
t = 1.25 s
The equation of the simple harmonic motion
y = A Sin ωt
y = A Sin (2 x π x f x t)
put, t = 1.25 s, A = 14.6 cm, f = 9.73 Hz
y = 14.6 Sin ( 2 x 3.14 x 9.73 x 1.25)
y = 14.6 Sin 76.38
y = 12.14 cm
Thus, the displacement of the particle from the equilibrium position is 12.14 cm.