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3 years ago

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An 73 cm long pendulum with a 0.80 kg bob is released from rest at an initial angle of θ0 with the vertical. at the bottom of th

e swing, the speed of the bob is 2.8 m/s. (a) what is θ0?

1 answer:

kipiarov [429]3 years ago

8 0

I dont know what the answer will be

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What is light intensity?

soldi70 [24.7K]

Light intensity is the "amount of light given off a light source." Also, is the measure the wavelength of the amount of light given off by a light source.

Hope this helps.

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2 years ago

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Why are different constellations<br> of stars seen during different<br> seasons?

slamgirl [31]

Actually, they're not. There's a group of stars and constellations arranged
around the pole of the sky that's visible at any time of any dark, clear night,
all year around. And any star or constellation in the rest of the sky is visible
for roughly 11 out of every 12 months ... at SOME time of the night.

Constellations appear to change drastically from one season to the next,
and even from one month to the next, only if you do your stargazing around
the same time every night.

Why does the night sky change at various times of the year ? Here's how to
think about it:

The Earth spins once a day. You spin along with the Earth, and your clock is
built to follow the sun . "Noon" is the time when the sun is directly over your
head, and "Midnight" is the time when the sun is directly beneath your feet.

Let's say that you go out and look at the stars tonight at midnight, when you're
facing directly away from the sun.

In 6 months from now, when you and the Earth are halfway around on the other
side of the sun, where are those same stars ? Now they're straight in the
direction of the sun. So they're directly overhead at Noon, not at Midnight.

THAT's why stars and constellations appear to be in a different part of the sky,
at the same time of night on different dates.

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3 years ago

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In a parallel circuit, if bulb #2 were to blow out, bulb #1 would stay lit or go out?

valkas [14]

Vhychhguuhkxkgxjgzkg

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3 years ago

or Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter it discards the fram

Artist 52 [7]

For Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter

a. it discards the frame without sending an error message to the network layer

b. it sends a NACK (not acknowledged frame) to the sending host

c. it delivers the frame to the network layer, and lets the network layer decide what to do

d. it discards the frame and sends an error message to the network layer

Answer:

Option A

Explanation:

The nodal address has to match the signal message address for it to function well but if the it doesn't match the nodal receiver address, it disregards it.

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3 years ago

1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly hori

Dovator [93]

Answer:

The net acceleration of the SUV is 0.429 meters per square second due west.

Explanation:

Statement is incomplete. Description is presented below:

<em>A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?</em>

According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force ( $F$ ), measured in newtons:

$\Sigma F = F - R -f = F_{net}$ (1)

Where:

$R$ - Resistance force, measured in newtons.

$f$ - Wind force, measured in newtons.

$F_{net}$ - SUV net force, measured in newtons.

If we know that $F = 2500\,N$ , $R = 500\,N$ and $f = 500\,N$ , then net force experimented by the SUV is:

$F_{net} = 2500\,N-500\,N-500\,N$

$F_{net} = 1500\,N$

The car has acceleration.

By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:

$a_{net} = \frac{F_{net}}{m}$ (2)

Where $m$ is the mass of the SUV, measured in kilograms.

If we know that $F_{net} = 1500\,N$ and $m = 3500\,kg$ , then the net acceleration of the car is:

$a_{net} = \frac{1500\,N}{3500\,kg}$

$a_{net} = 0.429\,\frac{m}{s^{2}}$

The net acceleration of the SUV is 0.429 meters per square second due west.

8 0

2 years ago