The formula to calculate velocity is

A steam turbine operates with 1.6 MPa and 350°C steam at its inlet and saturated vapor at 30°C at its exit. The mass flow rate o

WINSTONCH [101]

Answer:

638.8kW

Explanation:

The flow rate of the steam m = 22kg/s

The Pressure of the steam at the inlet of the turbine P1 = 1.6MPa

The temperature of the steam at the inlet of the turbine T1 = 350*C

Steam quality at the exit of the turbine x2 = 1.0

The temperature of the steam at the exit of the turbine T2 = 30*C

Power produced = 12,350kW

Assuming the turbine is running on a steady state, hence we neglect the effect of kinetic and potential energy we get:

If you refer to the superheated steam table for the specific enthalpy at a pressure of 1.6MPa and temperature of 350*C, we get

h1 = 3,146kJ/kg

Refer to the steam table for saturated gas at temperature 30*C to get the specific enthalpy value h2 = 2,556.81kJ/kg

The heat that comes out from the turbine can be defined from the balance of energy in the system, and is represented as

Ein - Eout = change in system Energy = 0

Thus Ein = Eout

mh1 = mh2 + Wout + Qout

Qout = m(hi-h2) - Wout

Qout = 22 x (3146-255.6) - 12350

Qout = 638.8kW

3 0

4 years ago

In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

5 0

3 years ago

Pluto was laying at rest in the sun and notices the smell of meat. He runs at 8 m/s to the smell of the meat. How fast is the do

Gnesinka [82]

Given parameters:

Initial velocity(body is at rest) = 0m/s

Final velocity = 8m/s

Time of acceleration = 2s

Unknown:

Acceleration of the dog = ?

Acceleration is defined as the change in velocity with time.

Mathematically;

Acceleration = $\frac{Final velocity - Initial velocity}{time taken}$

Now input the given parameters and solve;

Acceleration = $\frac{8-0}{2}$

Acceleration = 4m/s²

The dog is accelerating at a rate of 4m/s²

5 0

3 years ago

The pressure on a balloon holding 356 mL of an ideal gas is increased from 267 torr to 1.00 atm. What is the new volume of the b

Natalija [7]

Answer:

124.52 mL

Explanation:

from Boyle's Law,

PV = P'V' ................... Equation 1

Where P = Initial pressure of the gas, V = Initial volume of the gas, P' = Final pressure of the gas, V' = Final volume of the gas.

make V' the subject of the equation.

V' = PV/P'............. Equation 2

Given: P = 267 torr = (267×0.00131) = 0.34977 atm, V = 356 mL, P' = 1 atm

Substitute into equation 2

V' = (0.34977×356)/1

V' = 124.52 mL.

Hence the new volume of the balloon = 124.52 mL

4 0

3 years ago

A 550N object has a coefficient of .012 against a smooth surface. What

Brrunno [24]

Vertically, the object is in equilibrium, so that the net force in this direction is

∑ F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

∑ F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

4 0

3 years ago