Answer:
.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6
Step-by-step explanation:
.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6
Answer:
y=3x-7
Step-by-step explanation:
lines are parallel hence gradient from the equation in question is the same as the gradient of the equation to be found.. comparing to y=mx+c, eq in question has grad 3... from the formula y-y1=m(x-x1) where (x1,y1) is equal to the point in question
Do you mean 'nine and eighty four hundredths' in standard form? If so, it will be:
9.84
Answer:
0,5*0,5=0,25
Step-by-step explanation:
assuming a die of 6 faces
25
0,5 for < 4; 0,5 for < 3
You need the Law of Cosines here and you use it when you have 2 sides and an enclosed angle. The side across from the angle is the one we are looking for. The correct way to express the Law using what we have is the last choice above. Side RT is the unknown, and it is across from the angle that is enclosed between the 2 other sides.
