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Anna11 [10]
3 years ago
9

I'm really getting tired of the questions like these lol

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Step-by-step explanation:

(3x+3)(x+2)=

3x^2+6x+3x+6

=3x^2+9x+6

we get quadratic equation

find discriminant:

D=b^2-4ac=81-72=9

x=(-b±√D)/2a

x1=-6/6=-1

x2=-12/6=-2

one of the x values should be correct.

but why when I try to put values I get zero

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The water level varies from 12 inches at low tide to 52 inches at high tide. Low tide occurs at 9:15 a.m. and high tide occurs a
balandron [24]
52 inches - 12 inches = 40 inches
amplitude:  a = 40 inches / 2 = 20 

<span>f(x)=20cos(bx)+c</span>
the value of c is 32... since the centre of the has been moved up 32 units

the minimum amplitude =  32 - 20 = 12
the maximum amplitude = 32 + 20 = 52

<span>f(x)=20cos(bx)+32</span><span>
if the curve takes 6 1/4 hours from low to high tides (9:15 am to 3:30 pm)  then it will take 12 1/2 hours to complete a full cycle.

adjust the period by converting 12 1/2 hours to an angle measure.

360</span>°/12 = 30° 
30° / 12 = 15°

12 1/2 = 360° + 15° = 375°

f(x) = 20 cos(375°) + 32
f(x) = 20 * 0.97 + 32
f(x) = 19.4 + 32
f(x) = 51.4
5 0
3 years ago
Which of the following terms is defined as a set of all points in a plane that are a given distance from a point? Circle Line se
natita [175]

Answer: a circle

Step-by-step explanation:

It’s not any of the other ones

6 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
mash [69]

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket <em>y</em> in feet <em>x</em> seconds after launch is given by the equation:

y=-16x^2+165x+69

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let <em>y</em> = 0 and solve for <em>x: </em>

<em />0=-16x^2+165x+69<em />

We can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = -16, <em>b</em> = 165, and <em>c </em>= 69.

Substitute:

\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}

Evaluate:

\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}

Hence, our solutions are:

\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

7 0
3 years ago
Plz answer this. Plzzzzzzzzzzzzzzzzz
lana [24]

Answer:

2^3×6-5÷3-3×4^-4 solving 8×1÷0×0=8÷0= 8

5 0
3 years ago
Please help!!! I don’t understand
Allushta [10]

Answer:

first you would add 5 on both sides

then you should have 15y = 28

then you will divide 15 by 15

then do the same to 28

Step-by-step explanation:

4 0
3 years ago
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