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3 years ago

Next number in the sequence 1 4 9 16 25

Mathematics

2 answers:

n200080 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

1² = 1
2² = 4
3² = 9
4² = 16
5² = 25
6² =<u><em> 36</em></u>

Anarel [89]3 years ago

3 0

The next number in the sequence is 36.

Starting from 1, the number increases by 3, 1 + 3 = 4. But the next number, the number it's being increased by increases by 2. 3 + 2 = 5, 4 + 5 = 9. And again, 5 + 2 = 7, 7 + 9 = 16. And again. 7 + 2 = 9, 16 + 9 = 25. Therefore, it is increased to + 11, and the next number is 36.

I hope this helped, and you have a great day!

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If Seth used 4 ounces of black beans, how many beans did he use altogether?

musickatia [10]

Answer: 4 Ounces.

Step-by-step Explanation: I don't know the full context of the problem, but if Seth used 4 ounces, that means that he used 4 ounces all together.

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3 years ago

A biased coin is flipped twice.

Anni [7]

Answer:

0.48.

Step-by-step explanation:

There are 2 ways that a tail lands once:-

Tail + head or

head + tail.

Prob(Tail on one throw) = 0.4

Prob(Head on one throw) = 1 - 0.4 = 0.6.

Prob(Tail first then head) = 0.4 * 0.6 = 0.24

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8 0

2 years ago

I need some help with 22, 24, 25

valkas [14]

22 increases by 0.9
24 increases by 4 and 1/2
25 increases by 4.3
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5 0

3 years ago

Read 2 more answers

Beth read a total of 12 books over 7 months.

givi [52]

She has been with her book club for 49 months.

Step-by-step explanation:

Books read = 12 books

Time period = 7 months

Therefore,

12 books = 7 months

1 book = $\frac{7}{12}\ months$

Books read so far = 84 books

Total time period = x

84 books = x months

1 book = $\frac{x}{84}\ months$

Using both unit rates;

$\frac{x}{84}=\frac{7}{12}\\x=\frac{7}{12}*84\\x=\frac{588}{12}\\x=49\ months$

She has been with her book club for 49 months.

Keywords: Unit rates, multiplication

Learn more about multiplication at:

#LearnwithBrainly

8 0

3 years ago

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce

LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 kg.

92.82% of the sample means are between 75 kg and 83 kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that $\mu = 79, \sigma = 22$ .

What percentage of individual adult females have weights between 75 kg and 83 kg?

This percentage is the pvalue of Z when $X = 83$ subtracted by the pvalue of Z when $X = 75$ . So:

X = 83

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{83 - 79}{22}$

$Z = 0.18$

$Z = 0.18$ has a pvalue of 0.5714.

X = 75

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75- 79}{22}$

$Z = -0.18$

$Z = -0.18$ has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each sample, what percentage of the sample means are between 75 kg and 83 kg?

Now we use the Central Limit THeorem, when $n = 100$ . So $s = \frac{22}{\sqrt{100}} = 2.2.$