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ludmilkaskok [199]
3 years ago
7

Next number in the sequence 1 4 9 16 25

Mathematics
2 answers:
n200080 [17]3 years ago
7 0

Answer:

36

Step-by-step explanation:

  • 1² = 1
  • 2² = 4
  • 3² = 9
  • 4² = 16
  • 5² = 25
  • 6² =<u><em> 36</em></u>
Anarel [89]3 years ago
3 0

The next number in the sequence is 36.

Starting from 1, the number increases by 3, 1 + 3 = 4. But the next number, the number it's being increased by increases by 2. 3 + 2 = 5, 4 + 5 = 9. And again, 5 + 2 = 7, 7 + 9 = 16. And again. 7 + 2 = 9, 16 + 9 = 25. Therefore, it is increased to + 11, and the next number is 36.

I hope this helped, and you have a great day!

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If Seth used 4 ounces of black beans, how many beans did he use altogether?​
musickatia [10]

Answer: 4 Ounces.

Step-by-step Explanation: I don't know the full context of the problem, but if Seth used 4 ounces, that means that he used 4 ounces all together.

6 0
3 years ago
A biased coin is flipped twice.
Anni [7]

Answer:

0.48.

Step-by-step explanation:

There are 2 ways that a tail lands once:-

Tail + head or

head + tail.

Prob(Tail on one throw) = 0.4

Prob(Head on one throw) = 1 - 0.4 = 0.6.

Prob(Tail first then head) = 0.4 * 0.6 = 0.24

Head then tail has the same probability (0.6*0.4).

So the requred probability = 0.24 + 0.24

= 0.48.

8 0
2 years ago
I need some help with 22, 24, 25
valkas [14]
22 increases by 0.9
24 increases by 4 and 1/2
25 increases by 4.3
Just subtract the number from the number after it to find how to find the next numbers in the sequence
5 0
3 years ago
Read 2 more answers
Beth read a total of 12 books over 7 months.
givi [52]

She has been with her book club for 49 months.

Step-by-step explanation:

Books read = 12 books

Time period = 7 months

Therefore,

12 books = 7 months

1 book = \frac{7}{12}\ months    

Books read so far = 84 books

Total time period = x

84 books = x months

1 book = \frac{x}{84}\ months

Using both unit rates;

\frac{x}{84}=\frac{7}{12}\\x=\frac{7}{12}*84\\x=\frac{588}{12}\\x=49\ months

She has been with her book club for 49 months.

Keywords: Unit rates, multiplication

Learn more about multiplication at:

  • brainly.com/question/10699220
  • brainly.com/question/10703930

#LearnwithBrainly

8 0
3 years ago
Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce
LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 ​kg.

92.82% of the sample means are between 75 kg and 83 ​kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that \mu = 79, \sigma = 22.

What percentage of individual adult females have weights between 75 kg and 83 ​kg?

This percentage is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 75. So:

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 79}{22}

Z = 0.18

Z = 0.18 has a pvalue of 0.5714.

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75- 79}{22}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 ​kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each​ sample, what percentage of the sample means are between 75 kg and 83 ​kg?

Now we use the Central Limit THeorem, when n = 100. So s = \frac{22}{\sqrt{100}} = 2.2.

X = 83

Z = \frac{X - \mu}{s}

Z = \frac{83 - 79}{2.2}

Z = 1.8

Z = 1.8 has a pvalue of 0.9641.

X = 75

Z = \frac{X - \mu}{s}

Z = \frac{75-79}{2.2}

Z = -1.8

Z = -1.8 has a pvalue of 0.0359.

This means that 0.9641-0.0359 = 0.9282 = 92.82% of the sample means are between 75 kg and 83 ​kg.

8 0
3 years ago
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