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4 years ago

Help me Solve for n. 0.3(n-5)=0.4-0.2n

Mathematics

2 answers:

elena-14-01-66 [18.8K]4 years ago

8 0

Answer:

3.8

Step-by-step explanation:

i know because i got it right on the i-ready quiz

saw5 [17]4 years ago

3 0

Distribute
0.3n-1.5=0.4-0.2n
Add like terms
0.5n=1.9
Divide both sides by 0.5
n=3.8

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Help me plsssssssss its easy and show work please

babymother [125]

Answer:

» For x-intercept, y is zero

 y = x² - 12x + 32 

${ \tt{0 = {x}^{2} - 12x + 32 }} \\ { \tt{ {x}^{2} - 12x + 32 = 0 }} \\ { \tt{(x - 8)(x - 4) = 0}} \\ { \tt{x = 8 \: \: and \: \: 4}} \\ { \mathfrak{x - intercept : \: \: }}{ \boxed{ \tt{ \: (8, \: 0) \: \: and \: \: (4, \: 0) \: \: }}}$

 y = x² - 10x +24 :

${ \tt{0 = {x}^{2} - 10x + 24}} \\ { \tt{ {x}^{2} - 10x + 24 = 0}} \\ { \tt{(x - 6)(x - 4) = 0}} \\ { \tt{x = 6 \: \: and \: \: 4}} \\ { \mathfrak{x - intercept : \: \: }}{ \boxed{ \tt{ \: (6, \: 0) \: \: and \: \: (4, \: 0) \: \: }}}$

 y = x² + 10x + 16 :

${ \tt{0 = {x}^{2} + 10x + 16}} \\ { \tt{ {x}^{2} + 10x + 16 = 0 }} \\ { \tt{(x + 2)(x + 8) = 0}} \\ { \tt{x = - 2 \: \: and \: \: - 8}} \\ { \mathfrak{x - intercept : \: \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \: \: and \: \: ( - 8, \: 0) \: \: }}}$

 y = x² - 25 :

${ \tt{0 = {x}^{2} - 25}} \\ { \tt{ {x}^{2} = 25}} \\ { \tt{ \sqrt{ {x}^{2} } = \sqrt{25} }} \\ { \tt{x = \pm5}} \\ { \mathfrak{x - intercept : \: \: }}{ \boxed{ \tt{ \: (5, \: 0) \: \: and \: \: ( - 5, \: 0) \: \: }}}$

 y = x² + 8x + 12 :

${ \tt{0 = {x}^{2} + 8x + 12 }} \\ { \tt{ {x}^{2} + 8x + 12 = 0 }} \\{ \tt{(x + 2)(x + 6) = 0}} \\ { \mathfrak{x - intercept : \: \: }}{ \boxed{ \tt{ \: ( - 2, \: 0) \: \: and \: \: ( - 6, \: 0) \: \: }}}$

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3 years ago

What percentage of total hours was spent playing soccer

Setler [38]

Answer: You need to give more information for me to able to properly answer this question.

Step-by-step explanation:

5 0

3 years ago

3 minus 5 as an exponent

otez555 [7]

It’s 243 (fill out space)

6 0

3 years ago

Read 2 more answers

Find the radius if mADB=270° and length is 61.26 meters

love history [14]

Given:

In the given circle, ∠ADB = 270° and length of ADB = 61.26 m

To find the radius of the circle.

Formula

The formula to determine the radius is given by

$arc \ length =(\frac{\theta}{360})2 \pi r$

Substituting arc length = 61.26, $\theta= 270$ , we get;

$61.26 =(\frac{270}{360})2 (3.14) r$

$61.26 =4.71 r$

$13=r$

Thus, the radius is 13 m

6 0

3 years ago

According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg

Sati [7]

Answer:

a) Mean blood pressure for people in China.

b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d) 8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

f) 157.44mmHg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is two standard deviations from the mean or more, it is considered unusual.

In this question:

$\mu = 128, \sigma = 23$

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{135 - 128}{23}$

$Z = 0.3$

$Z = 0.3$ has a pvalue of 0.6179

1 - 0.6179 = 0.3821

38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{141 - 128}{23}$

$Z = 0.565$

$Z = 0.565$ has a pvalue of 0.7140

71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg.

This is the pvalue of Z when X = 125 subtracted by the pvalue of Z when X = 120. So

X = 125

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{125 - 128}{23}$

$Z = -0.13$

$Z = -0.13$ has a pvalue of 0.4483

X = 120

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{120 - 128}{23}$

$Z = -0.35$

$Z = -0.35$ has a pvalue of 0.3632

0.4483 - 0.3632 = 0.0851

8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?

From b), when X = 135, Z = 0.3

Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg.

f.) What blood pressure do 90% of all people in China have less than?

This is the 90th percentile, which is X when Z has a pvalue of 0.28. So X when Z = 1.28. Then

X = 120

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 128}{23}$

$X - 128 = 1.28*23$

$X = 157.44$

157.44mmHg

6 0

3 years ago