On a coordinate plane, a parabola opens up. It goes through (negative 8, negative 2), has a vertex at (negative 5, negative 6.5)
1 answer:
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Answer:
x-axis
Step-by-step explanation:
The asymptote is a straight line that the curve gets closer and closer to but never touches it.
The given exponential function is .
The given graph has a horizontal asymptote,
The equation of this horizontal asymptote is y=0.
This is also refers to as the x-axis.
Therefore the asymptote is the x-axis.
<h2>Hello!</h2>
The answer is:
The quadratic function that fits the given picture is:
We can solve the problem and find the correct function that fits the curve below by finding which function intercepts the y-axis at -5 (we can see it from the picture), also, we need to look for a function that represents a parabola opening upwards. We need to remember that when a parabola is opening upwards, its quadratic term coefficient is negative.
So, we can see that from the given functions, the only function that represents a parabola opening upwards and its y-intercept is located at y equal to -5 is the second option:
We have that :
We can see that the quadratic term (a) is negative, and the quadratic function intercepts the y-axis at y equal to -5.
Hence, the answer is:
The quadratic function that fits the given picture is:
Have a nice day!
Note: I have attached a picture for better understanding.